How do you find the derivative of # 2/(5x+1)^2#?

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Answer 1 · 2016-10-22T00:07:14

#(dy)/(dx)=-20/(5x+1)^3#

#y=2/(5x+1)^2=2(5x+1)^-2#

Let #u=5x+1#,

#d/(du)2u^-2=-4u^-3=-4(5x+1)^-3#

#d/(dx)5x+1=5#

Using chain rule, #(dy)/(dx)=(dy)/(du)*(du)/(dx)#,

#(dy)/(dx)=-4(5x+1)^-3*5#

#=-20(5x+1)^-3#

#=-20/(5x+1)^3#