A container with a volume of #12 L# contains a gas with a temperature of #150^o C#. If the temperature of the gas changes to #640 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-10-24T11:32:46

New volume is #18.15# #L#

We know that, #(P_1V_1)/T_1= (P_2V_2)/T_2#

So here,#P_1= P_2# = constant

#T_1=150^@C# = #(150+273)# #K#,
#T_2= 640# #K#

#V_1=12# #L#, #V_2=?#

So,
#V_2=(12xx640)/423#= #18.15# #L#