Question

Question #89a1e

Answer 1

`(dy)/(dx)=-6x^2sin(x^3)cos(x^3)`

Explanation:

`d/(dx)cos^2(x^3)`

We have to apply chain rule, where `u=cos(x^3)`

`(dy)/(du)=d/(du)u^2=2u=2cos(x^3)`

`(du)/(dx)=d/(dx)cos(x^3)=-3x^2sin(x^3)`

`(dy)/(dx)=(dy)/(du)*(du)/(dx)=2cos(x^3)*-3x^2sin(x^3)`

`=-6x^2sin(x^3)cos(x^3)`