The gas inside of a container exerts #8 Pa# of pressure and is at a temperature of #120 ^o K#. If the temperature of the gas changes to #60 ^oC# with no change in the container's volume, what is the new pressure of the gas?
1 Answer
Oct 28, 2016
Explanation:
#(p1)/"T1"# =#(p2)/"T2"#
#(8)/"120"# =#(p2)/"60"#
#p2# =#4 Pa#
