How do you five the standard form of the following quadratic equations and identify the constants a, b and c $3 x^{2} = 5 - 2 x$ $3x^2 = 5 - 2x$ ?

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How do you five the standard form of the following quadratic equations and identify the constants a, b and c $3 x^{2} = 5 - 2 x$ $3x^2 = 5 - 2x$ ?

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Answer 1 · 2016-10-30T21:43:41

The standard form of the quadratic equation is $3 x^{2} + 2 x - 5 = 0$ $3x^2 + 2x - 5 = 0$ , $a = 3$ $a = 3$ , $b = 2$ $b = 2$ , and $c = - 5$ $c = -5$ .

Explanation:

Standard form of a quadratic equation is $a x^{2} + b x + c = 0$ $ax^2 + bx + c = 0$ , so we will use inverse operations to get all the terms on the left , equal to $0$ $0$ on the right.

$3 x^{2} = 5 - 2 x$ $3x^2 = 5 - 2x$
$3 x^{2} + 2 x = 5 - 2 x + 2 x$ $3x^2 + 2x = 5 - 2x + 2x$
$3 x^{2} + 2 x = 5$ $3x^2 + 2x = 5$
$3 x^{2} + 2 x - 5 = 5 - 5$ $3x^2 + 2x - 5 = 5 - 5$
$3 x^{2} + 2 x - 5 = 0$ $3x^2 + 2x - 5 = 0$

Now that the quadratic equation is in standard form, we can identify the constants $a$ $a$ , $b$ $b$ , and $c$ $c$ .

$a = 3$ $a = 3$ , $b = 2$ $b = 2$ , and $c = - 5$ $c = -5$

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How do you five the standard form of the following quadratic equations and identify the constants a, b and c $3 x^{2} = 5 - 2 x$ $3x^2 = 5 - 2x$ ?

1 Answer

Explanation:

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How do you five the standard form of the following quadratic equations and identify the constants a, b and c 3x2=5−2x3x^2 = 5 - 2x?

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How do you five the standard form of the following quadratic equations and identify the constants a, b and c $3 x^{2} = 5 - 2 x$ $3x^2 = 5 - 2x$ ?