What is the derivative of #4 / (x+3)#?

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Answer 1 · 2016-11-01T14:49:10

#(dy)/(dx)=-4/(x+3)^2#

This problem can be solved with the use of the chain rule...

#y=4(x+3)^(-1)#

#y=4u^(-1)#

#(dy)/(du)=-4u^(-2)=-(4)/(u^2)=-(4)/(x+3)^2#

#u=x+3#

#(du)/(dx)=1#

#(dy)/(du)*(du)/(dx)=-4/(x+3)^2=(dy)/(dx)#