Question

How do you integrate `int 1/(2x^3)dx`?

Answer 1

`int 1 /(2x^3) dx = (-1)/(4x^2 ) + C`

Explanation:

Using the power rule we have:

`int 1/(2x^3) dx = int1/2x^-3dx`

`= 1/2(x^-2/-2) + C`
`= (-1)/(4x^2 ) + C`