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How do you simplify the expression $\frac{{sec}^{2} t - 1}{tan t}$ $(sec^2t-1)/tant$ ?

1 Answer

Rajat Chatterjee

Nov 3, 2016

ans. $tan t$ $tant$ .

Explanation:

$\frac{{sec}^{2} t - 1}{tan t}$ $(sec^2t-1)/tant$ = $\frac{{tan}^{2} t}{tan t}$ $tan^2t/tant$ = $tan t$ $tant$ .

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