How do you compute the 9th derivative of: #arctan((x^3)/2)# at x=0 using a maclaurin series?
1 Answer
Nov 4, 2016
It should be
Explanation:
The Mac Laurin series of
If we replace the variable
it becomes
that rewritten assumes the form
By recalling that in the Maclaurin series the coefficient of the each term of n degree is just the n-th derivative of
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