What is the vertex form of $y= (x-14)(3x+4)-x^2+2x$ ?

Question

1530 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-06T22:28:17

$y=2(x-9)^2-218$

$y=3x^2+4x-42x-56-x^2+2x=2x^2-36x-56$

If we complete the square with thefirst two terms

$y=2(x-9)^2-162-56=2(x-9)^2-218$

What is the vertex form of y= (x-14)(3x+4)-x^2+2x y= (x-14)(3x+4)-x^2+2x?