What is the average speed of an object that is moving at $9 \frac{m}{s}$ $9 m/s$ at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = 5 - 2 t$ $a(t) =5-2t$ on $t \in [0, 5]$ $t in [0,5]$ ?

Question

What is the average speed of an object that is moving at $9 \frac{m}{s}$ $9 m/s$ at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = 5 - 2 t$ $a(t) =5-2t$ on $t \in [0, 5]$ $t in [0,5]$ ?

1 Answer

Impact of this question

1764 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-08T14:39:22

Average speed is the mean of initial velocity and final velocity.

to solve this question we need to take out final velocity ( $v$ $v$ ) and initial velocity( $u$ $u$ ) is already proided.

so lets proceed.

$a (t) = 5 - 2 t$ $a(t)=5-2t$
therefore accereleration at 5 seconds is -5 $\frac{m}{s^{2}}$ $m/s^2$ .This is derieved by puting t=5 in the above equation/function.

$a = \frac{v}{t} - \frac{u}{t}$ $a=v/t-u/t$

by putting values this we get $v = - 12 \frac{m}{s}$ $v=-12m/s$

so $u = 9 \frac{m}{s}$ $u=9m/s$ and $v = - 12 \frac{m}{s}$ $v=-12m/s$

$V_{a} v = \frac{u + v}{2}$ $V_av= (u+v)/2$
= $- 1.5 \frac{m}{s}$ $-1.5m/s$ .

I haven't showed the actual mathematics calculation as i hope you can easily make it,she see the procedure.

Science

Math

Humanities

... and beyond

What is the average speed of an object that is moving at $9 \frac{m}{s}$ $9 m/s$ at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = 5 - 2 t$ $a(t) =5-2t$ on $t \in [0, 5]$ $t in [0,5]$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the average speed of an object that is moving at 9ms9 m/s at t=0t=0 and accelerates at a rate of a(t)=5−2ta(t) =5-2t on t∈[0,5]t in [0,5]?

1 Answer

Related questions

Impact of this question

What is the average speed of an object that is moving at $9 \frac{m}{s}$ $9 m/s$ at $t = 0$ $t=0$ and accelerates at a rate of $a (t) = 5 - 2 t$ $a(t) =5-2t$ on $t \in [0, 5]$ $t in [0,5]$ ?