What is f(x) = int 1/(x-3)-x/(x+4) dx if f(-1)=6 ? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Alberto P. Nov 9, 2016 f(x)=-x+lnabs(x-3)+4lnabs(x+4)+5-2ln2-4ln3 Explanation: f(x)=lnabs(x-3)-int(y+4)/ydy + c = -y+4lnabsy+lnabs(x-3)+c=-x+4lnabs(x+4)+lnabs(x-3)+c Then f(-1)= 6 so 6=1+4ln3+ln4+c c=5-4ln3-3ln2 Answer link Related questions How do you find the constant of integration for intf'(x)dx if f(2)=1? What is a line integral? What is f(x) = int x^3-x if f(2)=4 ? What is f(x) = int x^2+x-3 if f(2)=3 ? What is f(x) = int xe^x if f(2)=3 ? What is f(x) = int x - 3 if f(2)=3 ? What is f(x) = int x^2 - 3x if f(2)=1 ? What is f(x) = int 1/x if f(2)=1 ? What is f(x) = int 1/(x+3) if f(2)=1 ? What is f(x) = int 1/(x^2+3) if f(2)=1 ? See all questions in Evaluating the Constant of Integration Impact of this question 1410 views around the world You can reuse this answer Creative Commons License