How do you write the equation of the line with slope 2/3 through the point (-3, -7) in slope-intercept form?

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Answer 1 · 2016-11-10T17:35:06

y= #2/3# x -5

First write the equation in point-slope form.

The formula is: #(y-y_1)=m(x-x_1).#

#:.#It would be y+7=#2/3# (x+3).

Next solve it for y to get the slope intercept form:

y+7 = #(2x)/3# +2 , or,

y= #2/3# x -5

This is the point slope form. Slope is #2/3# and y intercept is -5