Consider this quadratic function $f (x) = 2 x^{2} - 8 x + 1$ $f(x)=2x^2-8x+1$ , how do you find the axis of symmetry?

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Consider this quadratic function $f (x) = 2 x^{2} - 8 x + 1$ $f(x)=2x^2-8x+1$ , how do you find the axis of symmetry?

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Answer 1 · 2016-11-12T04:10:19

The equation of the axis of symmetry for $f (x) = 2 x^{2} - 8 x + 1$ $f(x) = 2x ^2 - 8x + 1$ is $x = 2$ $x = 2$ .

Explanation:

This quadratic function is in standard form, $f (x) = a x^{2} + b x + c$ $f(x) = ax^2 + bx + c$ .
For every quadratic function in standard form the axis of symmetry is given by the formula $x = \frac{- b}{2 a}$ $x = (-b)/(2a)$ .

In $f (x) = 2 x^{2} - 8 x + 1$ $f(x) = 2x^2 - 8x + 1$ , $a = 2$ $a = 2$ , $b = - 8$ $b = -8$ , and $c = 1$ $c = 1$ . So, the equation for the axis of symmetry is given by

$x = \frac{- (- 8)}{2 \cdot 2}$ $x = (-(-8))/(2*2)$

$x = \frac{8}{4}$ $x = 8/4$

$x = 2$ $x = 2$

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Consider this quadratic function $f (x) = 2 x^{2} - 8 x + 1$ $f(x)=2x^2-8x+1$ , how do you find the axis of symmetry?

1 Answer

Explanation:

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Science

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Consider this quadratic function f(x)=2x^2-8x+1f(x)=2x2−8x+1f(x)=2x^2-8x+1, how do you find the axis of symmetry?

1 Answer

Explanation:

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Consider this quadratic function $f (x) = 2 x^{2} - 8 x + 1$ $f(x)=2x^2-8x+1$ , how do you find the axis of symmetry?