Calculate the enthalpy of formation of acetic acid if its anthalpy of combustion to CO2 and H2O is - 867 kJ/mol and the enthalpies of formation of CO2 and H2O are respectively - 393.5 and -285.9 kJ / mol ?

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Answer 1 · 2016-11-12T07:03:13

-491.8kJ/mol

Combustion reaction for above question is

#C_2H_4O_2 + 2O_2 -> 2CO_2 + 2H_2O#

#DeltaH_f(combustion) = 2[DeltaH_(CO_2) + DeltaH_(H_2O)] - DeltaH_(C_2H_4O_2)#

#DeltaH_(C_2H_4O_2) = 2[DeltaH_(CO_2) + DeltaH_(H_2O)] -DeltaH_(combustion)#

#DeltaH_(C_2H_4O_2) = 867+(2times-679.4) = -491.8(kJ)/(mol)#