How do you solve #\sqrt { 3x - 22} = \sqrt { 10- x }#?

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Answer 1 · 2016-11-14T22:28:28

#x=8#

We need to get rid of the radicals (square roots), so square both sides.

#(sqrt(3x - 22))^2 = (sqrt(10-x))^2#

Now we have, which is much easier to deal with

#3x-22=10-x#

Add the variable #x# to both sides.

#4x-22= 10#

Add #22# to both sides.

#4x= 32#

Divide both sides by #4# to isolate #x#

#x=8#

Hope that helps!