How do you simplify $4 (2 - 3 i) + 6 i$ $4(2-3i)+6i$ ?

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How do you simplify $4 (2 - 3 i) + 6 i$ $4(2-3i)+6i$ ?

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Answer 1 · 2016-11-15T10:58:56

The simplified complex number is $8 - 6 i$ $8 - 6i$ .

Explanation:

Begin by distributing the $4$ $4$ , then combine like terms. Remember that the standard form of a complex number requires that imaginary part be stated after the real part.

$4 (2 - 3 i) + 6 i$ $4(2 - 3i) + 6i$
$8 - 12 i + 6 i$ $8 - 12i + 6i$
$8 - 6 i$ $8 - 6i$

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How do you simplify $4 (2 - 3 i) + 6 i$ $4(2-3i)+6i$ ?

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How do you simplify 4(2−3i)+6i4(2-3i)+6i?

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How do you simplify $4 (2 - 3 i) + 6 i$ $4(2-3i)+6i$ ?