How do you evaluate #58+(-22)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Suresh Rawal Dec 6, 2016 36 Explanation: 58+(-22) # 58+/- = -22# or #58-22=36# Hence answer is 36 Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 1706 views around the world You can reuse this answer Creative Commons License