A function is given as #f(x)=2x^2 -12x+ 3#. How do you write the vertex form of the given equation?

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Answer 1 · 2016-12-08T02:55:28

#2(x-3)^2 - 15#

vertex form is #a(x - h)^2 + k#

#2x^2 -12x +3#

#2(x^2-6x) +3#

#2(x^2-6x+9-9) +3#

#2(x^2-6x+9) +3 -18#

#2(x-3)^2 -15#

which tells us that it is a positive graph with vertex ( 3, -15 )