Question #28b82

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Answer 1 · 2016-12-10T10:09:56

The acceleration is: $a = \frac{250}{3} \frac{m}{s^{2}}$ $a=250/3 m/(s^2)$

if the force $F$ $F$ is applied to a body with mass $m$ $m$ the acceleration is:

$\to a = \frac{\to F}{m}$ $vec(a)=vec(F)/m$

If we substitute the given data we get:

$\to a = \frac{\to F}{m} = \frac{25}{0.3} = \frac{250}{3}$ $vec(a)=vec(F)/m=25/0.3=250/3$