Question

How do you differentiate `f(x) = (sinx)/(x^3-x)` using the quotient rule?

Answer 1

If `f(x)=sin(x)/(x^3-x)`

`f'(x)=[d/dxsin(x)*(x^3-x)-d/dx(x^3-x)*sin(x)]/(x^3-x)^2`

`=[cos(x)*(x^3-x)-(3x^2-1)*sin(x)]/(x^3-x)^2`