How do you simplify $\frac{x}{7 x - 3} + \frac{x + 2}{15 x + 30}$ $x/(7x-3)+(x+2)/(15x+30)$ ?

Question

1953 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-15T21:01:27

$\frac{x}{7x - 3}$ $"x"/"7x - 3"$ + $\frac{x + 2}{15x + 30} = \frac{22x - 3}{105x - 45}$ $"x + 2"/"15x + 30" = "22x - 3"/"105x - 45"$

$\frac{x}{7x - 3} + \frac{x + 2}{15x + 30}$ $"x"/"7x - 3" +" x + 2"/"15x + 30"$

$\frac{x}{7x - 3} + \frac{x + 2}{15(x + 2)}$ $"x"/"7x - 3" +" x + 2"/"15(x + 2)"$

$\frac{x}{7x - 3} + \frac{1}{15}$ $"x"/"7x - 3" +"1"/"15"$

$\frac{15x + 7x - 3}{(7x - 3)(15)}$ $"15x + 7x - 3"/"(7x - 3)(15)"$

$\frac{22x - 3}{(7x)(15) - (3)(15)}$ $"22x - 3"/"(7x)(15) - (3)(15)"$

$\frac{22x - 3}{105x - 45}$ $"22x - 3"/"105x - 45"$

How do you simplify x7x−3+x+215x+30x/(7x-3)+(x+2)/(15x+30)?