How do you divide $\frac{- 7 - 7 i}{- 7 - 4 i}$ $(-7-7i)/(-7-4i)$ ?

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How do you divide $\frac{- 7 - 7 i}{- 7 - 4 i}$ $(-7-7i)/(-7-4i)$ ?

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Answer 1 · 2017-01-21T20:53:51

For a complex number in this form, you need to multiply the numerator and denominator by the conjugate of the denominator: $- 7 + 4 i$ $-7+4i$

Explanation:

$\frac{(- 7 - 7 i) (- 7 + 4 i)}{(- 7 - 4 i) (- 7 + 4 i)}$ $((-7-7i)(-7+4i))/((-7-4i)(-7+4i))$
This will have the effect of eliminating the imaginary numbers in the denominator!
$(49 - 28 i + 49 i - 28 i^{2})$ $(49-28i+49i-28i^2)$ = $49 + 28 + 21 i$ $49+28+21i$ = $77 + 21 i$ $77+21i$ for the numerator.

$49 - 28 i + 28 i - 16 i^{2}$ $49-28i+28i-16i^2$ = $49 + 16$ $49+16$ = 65 for the denominator.
Final answer: $\frac{77 + 21 i}{65}$ $(77+21i)/65$ .
Some textbooks require "a+bi" form: $\frac{77}{65} + \frac{21 i}{65}$ $77/65+(21i)/65$

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How do you divide $\frac{- 7 - 7 i}{- 7 - 4 i}$ $(-7-7i)/(-7-4i)$ ?

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Explanation:

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How do you divide (-7-7i)/(-7-4i)−7−7i−7−4i(-7-7i)/(-7-4i)?

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How do you divide $\frac{- 7 - 7 i}{- 7 - 4 i}$ $(-7-7i)/(-7-4i)$ ?