How do write in simplest form given #-23.94div10.5#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Barney V. Jan 22, 2017 #-2.28# Explanation: #-23.94-:10.5# #=-23 cancel94^47/cancel100^50 -:cancel105^21/cancel10^2# #=-23 47/50-:21/2# #=-23 47/50 xx 2/21# #=-1197/cancel50^25 xx cancel2^1/21# #=-1197/25 xx 1/21# #=-1197/525# #=-2.28# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 2048 views around the world You can reuse this answer Creative Commons License