A triangle has corners A, B, and C located at (3 ,1 )(3,1), (6 ,4 )(6,4), and (9 ,8 )(9,8), respectively. What are the endpoints and length of the altitude going through corner C?

1 Answer
Feb 2, 2017
  1. First find the line ABAB
  2. Then find the line ll perpendicular to ABAB (the line of altitude) such that it intersects with point CC
  3. Then find the point DD at which ll intersects with ABAB
  4. Then use the distance formula with the points CC and DD to get the distance of the altitude.

See if you can do it step by step. If not, keep on reading.

Step 1

Find the equation for ABAB

y-y_1=m(x-x_1)yy1=m(xx1) (point slope formula)

m = (4-1)/(6-3) = 1m=4163=1 (finding the slope using the points AA and BB)

y-1=x-3y1=x3 (plugging mm and A back into the equation, you could choose A or B and it would be the same)

Segment ABAB lies on the line y=x-2y=x2

Step 2

Find line ll that is perpendicular to ABAB and intersects with CC.

y = mx + by=mx+b (start with an empty line)

y = -1x + by=1x+b (negative reciprocal slope of ABAB for perpendicular line)

8 = -9 + b8=9+b (substitute in point CC to find a line that intersects with CC)

b = 17b=17 (solve)

Now that we have bb we can list the equation.

ll, our altitude, has the equation y = -x+17y=x+17

Step 3

Find point DD where our altitude ll and base ABAB intersect

y = -x+17y=x+17 (ll)
y=x-2y=x2 (ABAB)

So -x+17=x-2x+17=x2
19=2x19=2x
x = 9.5x=9.5
y = 7.5y=7.5 (by plugging xx back into one of the equations)

So #D = (9.5,7.5)

Step 4

Find the distance of CDCD

sqrt((9-9.5)^2+(8-7.5)^2)(99.5)2+(87.5)2

= sqrt(2)/2=22

Hm.. the answer doesn't look quite right. Whoops.