Question #294f3

1 Answer
Feb 10, 2017

#y=(-x)/(x-1)#

Explanation:

So, you're given #f(x) = x/(x+1)#. To find the inverse, or #f^-1(x)#, there are 2 steps:

  1. "Replace the #x# and #y# (or #f(x)#) variables"
  2. Solve for #y# in terms of #x#

So, first we replace and get #x=y/(y+1)#.

Now, the best strategy to solve for #y# is to follow these steps:
1. multiply out all of the denominators with variables to bring them into the numerator
2. move all of the terms with the variable you're looking for (#y#) to one side
3. Factor out that variable
4. Divide to isolate the variable

Step #1#:
#(y+1)*x = y/(y+1)(y+1)#

#x*y+x = y#

Step #2#:
#x*y-y=-x#

Step #3#:
#y(x-1) = -x#

Step #4#:
#y = -x/(x-1)#