How do you solve #4sqrt(3m^2-15)=4#?

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Answer 1 · 2017-02-20T21:15:59

#m=sqrt(16/3)# and #-sqrt(16/3)#

Divide 4 on both sides:

#(4/4)sqrt(3m^2-15)=(4/4)#

The fours cancel leaving:

#sqrt(3m^2-15)=1#

Square both sides to get rid of the square root. Note that when you do this, it will become positive or negative 1

#3m^2-15=1#

Add 15 to both sides.

#3m^2=16#

Divide 3 on both sides.

#m^2=16/3#

Finally, square root both sides to get rid of the square. Note that this will give you the positive and the negative of the answer

#m=sqrt(16/3)# and #-sqrt(16/3)#