A charge of $24 C$ $24 C$ passes through a circuit every $18 s$ $18 s$ . If the circuit can generate $16 W$ $16 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-03-05T12:06:13

$9Omega$

You can work out the current by charge and time,

$I = Q/t = 24/18 = 1.33A$

which you can then use to work out power, by

$P = IV = I(IR) = I^2R$

Since we know current and power, and we want the resistance, then

$R = P/I^2 = 16/1.33^2 = 9Omega$

A charge of 24 C24C24 C passes through a circuit every 18 s18s18 s. If the circuit can generate 16 W16W16 W of power, what is the circuit's resistance?