How do you integrate $\int d x$ $int dx$ ?

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Answer 1 · 2017-03-05T12:15:47

$x + C$ $x + C$

$\int d x = \int 1 d x = \int x^{0} d x$ $intdx = int1dx = intx^0dx$

Using the standard power rule of integration,

$\int x^{0} d x = \frac{x^{0 + 1}}{0 + 1} + C = x + C$ $intx^0dx = x^(0+1)/(0+1) + C= x + C$

Answer 2 · 2017-03-05T12:16:17

$x + C$ $x+C$

$\int d x = \int x^{0} d x$ $int dx = int x^0 dx$

Applying the power rule:

$\int d x = \frac{x^{0 + 1}}{0 + 1} + C$ $int dx= x^(0+1)/(0+1) +C$

$= x + C$ $=x+C$

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