A charge of $18 C$ $18 C$ passes through a circuit every $12 s$ $12 s$ . If the circuit can generate $4 W$ $4 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-03-05T15:55:24

Calculate the current by dividing charge by time:

$I = \frac{Q}{t} = \frac{18 C}{12 s} = 1.5 A$ $I = Q/t = (18C)/(12s) = 1.5A$

$P = I V = I (I R) = I^{2} R$ $P = IV = I(IR) = I^2R$

Therefore,

$R = P/I^2 = (4W)/(1.5A)^2=1.78Omega$

A charge of 18 C18C18 C passes through a circuit every 12 s12s12 s. If the circuit can generate 4 W4W4 W of power, what is the circuit's resistance?