A charge of #24 C# passes through a circuit every #6 s#. If the circuit can generate #12 W# of power, what is the circuit's resistance?

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2 Answers
reudhreghs
Mar 5, 2017

#0.75Omega#

Explanation:

Calculate current, #I#, by

#I = Q/t = (24C)/(6s) = 4A#

Electrical power is given by

#P = IV = I^2R#

so

#R = P/I^2 = (12W)/(4A)^2 = 0.75Omega#

reudhreghs
Mar 5, 2017

#0.75Omega#

Explanation:

Calculate current, #I#, by

#I = Q/t = (24C)/(6s) = 4A#

Electrical power is given by

#P = IV = I^2R#

so

#R = P/I^2 = (12W)/(4A)^2 = 0.75Omega#

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