How do you find the antiderivative of $f (x) = 8 x$ $f(x)=8x$ ?

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Answer 1 · 2017-03-06T12:41:06

$4 x^{2} + C$ $4x^2 + C$

Use the standard power rule for integration,

$\int a x^{n} d x = \frac{a x^{n + 1}}{n + 1} + C$ $intax^ndx = (ax^(n+1))/(n+1) + C$

so

$\int 8 x^{1} d x = \frac{8 x^{2}}{2} + C = 4 x^{2} + C$ $int8x^1dx = (8x^2)/2 + C = 4x^2 + C$

How do you find the antiderivative of f(x)=8xf(x)=8xf(x)=8x?