What is the path length in centimeters when the transmittance is $0.692$ , the molar absorptivity is $7.39 xx 10^4 "L/(mol.cm)"$ and the concentration is $0.0000923 M$ ?

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Answer 1 · 2017-03-27T21:36:12

$"0.101 cm"$

Beer's Law:

$"Absorbance" = ("molar absorptivity") xx ("path length") xx ("concentration")$

or

$A = e xx Lxx c$

So

$L = A/ (e c)$

$L = 0.692 / ((7.39*10^4L/(mol*cm) * (9.23*10^-5 (mol)/L))$

$L = "0.101 cm"$

What is the path length in centimeters when the transmittance is 0.6920.692, the molar absorptivity is 7.39 xx 10^4 "L/(mol.cm)"7.39 xx 10^4 "L/(mol.cm)" and the concentration is 0.0000923 M0.0000923 M?