Question

How do you find the derivative of `s=tan^2t`?

Answer 1

`(ds)/dt=2tan t sec^2 t`

Explanation:

`s=tan^2 x=(tan t)^2`

By Power Rule and Chain Rule,

`(ds)/dt=2(tan t)^1 (tan t)'=2tan t sec^2 t`

I hope that this was clear.