How do you differentiate #f(x)= ( x + 1 )/ ( secx )# using the quotient rule?

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Answer 1 · 2017-04-11T14:05:52

#f'(x)=(1-(x+1)tan x)/(sec x)#

#f'(x)=(1 cdot sec x-(x+1)cdot sec x tan x)/(sec^2 x)#

By factoring out #sec x# from the numerator,

#=(sec x(1-(x+1)tan x))/(sec^2 x)#

By cancelling #sec x#,

#=(1-(x+1)tan x)/(sec x)#

I hope that this was clear.