Question

Question #5cc93

Answer 1

`x=1/3`

`x=-2/3+-i`

Explanation:

Subtract `13` from both sides

`27x^3+27x^2+27x-13=0`

This can factored

`(3x-1)(9x^2+12x+13)=0`

So,

`3x-1=0`

`3x=1`

`x=1/3`

`9x^2+12x+13=0`

Use the quadratic formula

`(-12+-sqrt((12)^2-4(9)(13)))/(2(9))`

`(-12+-sqrt(144-468))/18`

`(-12+-sqrt(324)i)/18`

`-12/18+-(18i)/18`

`-2/3+-i`