How do you simplify $(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5})$ $(-2a^-2 b^4)(3a^2 b^-5)$ ?

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How do you simplify $(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5})$ $(-2a^-2 b^4)(3a^2 b^-5)$ ?

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Answer 1 · 2017-04-18T12:36:33

$- 6 b^{- 1}$ $-6b^-1$

Explanation:

$(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5}) = - 2 \cdot 3 (a^{- 2} b^{4}) (a^{2} b^{- 5})$ $(-2a^-2b^4)(3a^2b^-5) = -2*3(a^-2b^4)(a^2b^-5)$
$= - 6 (a^{- 2} a^{2}) (b^{4} b^{- 5})$ $= -6(a^-2a^2)(b^4b^-5)$
$= - 6 (a^{- 2 + 2}) (b^{4 - 5})$ $= -6(a^(-2+2))(b^(4-5))$
$= - 6 a^{0} b^{- 1}$ $= -6a^0b^-1$
$= - 6 b^{- 1}$ $= -6b^-1$

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How do you simplify $(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5})$ $(-2a^-2 b^4)(3a^2 b^-5)$ ?

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Explanation:

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How do you simplify $(- 2 a^{- 2} b^{4}) (3 a^{2} b^{- 5})$ $(-2a^-2 b^4)(3a^2 b^-5)$ ?