How do you find the zero of #f(x)=1/2x+6#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer kamil9234 Apr 20, 2017 #x=-12# Explanation: #0=(1/2)*x+6# #(1/2)x=-6# #x=-12# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 2989 views around the world You can reuse this answer Creative Commons License