How do you find $y= -2(x-10)² + 17$ the vertex?

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Answer 1 · 2017-04-23T18:23:09

$(10,17)$

since it’s already in the vertex form $y=a(x-h)+k$

So it’s pretty easy to find the vertex which equals $(h,k)$

so the vertex here from the function $y=2(x-10)^2+17$

is equal to $(10,17)$

How do you find y= -2(x-10)² + 17y= -2(x-10)² + 17 the vertex?