What is the 2nd term in expansion of ${(3 u - 1)}^{3}$ $(3u-1)^3$ ?

Question

What is the 2nd term in expansion of ${(3 u - 1)}^{3}$ $(3u-1)^3$ ?

1 Answer

Impact of this question

3431 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-24T15:34:52

$- 27 u^{2}$ $-27u^2$

Explanation:

${(3 u - 1)}^{3} = 1 \cdot ({(3 u)}^{3} \cdot {(- 1)}^{0}) + 3 \cdot ({(3 u)}^{2} \cdot {(- 1)}^{1}) + 3 \cdot ({(3 u)}^{1} \cdot {(- 1)}^{2}) + 1 \cdot ({(3 u)}^{0} \cdot {(- 1)}^{3}) .$ $(3u-1)^3 = 1*((3u)^3*(-1)^0) + 3*((3u)^2*(-1)^1) + 3*((3u)^1*(-1)^2) + 1*((3u)^0*(-1)^3).$
If you look closely, the sum of powers in each term on the right hand side of the equation above is 3.
Now, the 2nd term:
$- 3 \cdot 9 u^{2} \cdot 1 = - 27 u^{2} .$ $-3*9u^2*1 = -27u^2.$

Science

Math

Humanities

... and beyond

What is the 2nd term in expansion of ${(3 u - 1)}^{3}$ $(3u-1)^3$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the 2nd term in expansion of (3u-1)^3(3u−1)3(3u-1)^3?

1 Answer

Explanation:

Related questions

Impact of this question

What is the 2nd term in expansion of ${(3 u - 1)}^{3}$ $(3u-1)^3$ ?