How do you sketch the graph of #y=x^2+0.5# and describe the transformation?

1 Answer
Apr 27, 2017

Pick some easy points for #x#.

Explanation:

Let's choose #x=-3,-2,-1,0,1,2,3#
With these points we get the following
#y(-3)=(-3)^2+0.5=9+0.5=9.5#
#y(-2)=(-2)^2+0.5=4+0.5=4.5#
#y(-1)=(-1)^2+0.5=1+0.5=1.5#
#y(0)=(0)^2+0.5=0+0.5=0.5#
#y(1)=(1)^2+0.5=1+0.5=1.5#
#y(2)=(2)^2+0.5=4+0.5=4.5#
#y(3)=(3)^2+0.5=9+0.5=9.5#

We can plot the following points to get
graph{x^2+0.5 [-11.21, 11.29, -0.75, 10.5]}
Since 0.5 is added after #x# is "modified," it will move the function #y=x^2# up by half a unit.