Question

What is the vertex form of `y= (x +6)(x/3 + 2)`?

Answer 1

`y=1/3(x+6)^2`

Explanation:

First you need to expan this function
`y=1/3x^2+4x+12`
And then I need to make this function transform as this type
`y=a(x-h)^2+k`
So
`y=1/3(x^2+12x+36)+12-12`
Final
`y=1/3(x+6)^2`