What is the vertex form of $y = (x + 6) (\frac{x}{3} + 2)$ $y= (x +6)(x/3 + 2)$ ?

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What is the vertex form of $y = (x + 6) (\frac{x}{3} + 2)$ $y= (x +6)(x/3 + 2)$ ?

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Answer 1 · 2017-04-28T13:16:34

$y = \frac{1}{3} {(x + 6)}^{2}$ $y=1/3(x+6)^2$

Explanation:

First you need to expan this function
$y = \frac{1}{3} x^{2} + 4 x + 12$ $y=1/3x^2+4x+12$
And then I need to make this function transform as this type
$y = a {(x - h)}^{2} + k$ $y=a(x-h)^2+k$
So
$y = \frac{1}{3} (x^{2} + 12 x + 36) + 12 - 12$ $y=1/3(x^2+12x+36)+12-12$
Final
$y = \frac{1}{3} {(x + 6)}^{2}$ $y=1/3(x+6)^2$

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What is the vertex form of $y = (x + 6) (\frac{x}{3} + 2)$ $y= (x +6)(x/3 + 2)$ ?

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Explanation:

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What is the vertex form of $y = (x + 6) (\frac{x}{3} + 2)$ $y= (x +6)(x/3 + 2)$ ?