How do you solve 6x^2+5x=1?

2 Answers
Apr 29, 2017

Re-arranging we get:

6x^2 + 5x - 1 = 0

We can write this as:

6x^2 + 6x - x - 1 = 0

i.e. 6x(x + 1) - (x + 1) = 0

=> (6x - 1)(x + 1) = 0

so, x = 1/6 or x = -1

:)>

Apr 29, 2017

x=-1" or " x=1/6

Explanation:

"subtract 1 from both sides and equate to zero"

6x^2+5x-1=1-1

rArr6x^2+5x-1=0

"using the a-c method of factorising"

"require the factors of the product " -6" which sum to +5"

"the factors are " +6, -1

rArr6x^2+6x-x-1=0larr" split 5x"

rArr6x(x+1)-1(x+1)=0larr" factor pairs"

(x+1)(6x-1)=0larr" factor out (x+1)"

(x+1)=0rArrx=-1

(6x-1)=0rArrx=1/6

rArrx=-1" or " x=1/6" are the solutions"