Question #4187f Chemistry Gases Gas Stoichiometry 1 Answer MM May 3, 2017 120 mL Explanation: #n mol C_6H_6 = (39g)/(78g/(mol)# = #0.4997mol# #(15mol O_2)/(2 mol C_6H_6) times 0.4997 mol C_6H_6# = #3.784mol O_2# #Grams O_2 = mass O_2 = n times MW O_2 = 3.784 times 32 = 119.9g# Density liquid #O_2 = 1.1 g/(mL), therefore,# amount in grams = 119.9 Answer link Related questions How do you apply gas stoichiometry? How do you solve a gas law stoichiometry problem? How do you do gas stoichiometry problems at STP? When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... See all questions in Gas Stoichiometry Impact of this question 1873 views around the world You can reuse this answer Creative Commons License