How do you write an equation in standard form given point (-2,5) and slope 1?
2 Answers
y = x+7
Explanation:
-
Use the formula y=mx+c
m = gradient of graph
c= y intercept -
Substitute y,m and x in equation to find c
#5=1*-2 +c#
#5=-2+c#
7=c -
Replace m and c with numbers found
Therefore equation is y = x + 7
Explanation:
#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
#"where A is a positive integer and B, C are integers"#
#"begin by expressing the equation in "color(blue)"point-slope form"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"#
#"here " m=1" and " (x_1,y_1)=(-2,5)#
#y-5=1(x-(-2))#
#rArry-5=x+2larrcolor(red)" in point-slope form"#
#"subtract y from both sides"#
#cancel(y)cancel(-y)-5=x+2-y#
#rArr-5=x+2-y#
#"subtract 2 from both sides"#
#-5-2=xcancel(+2)cancel(-2)-y#
#rArr-7=x-y " or "#
#x-y=-7larrcolor(red)" in standard form"#