How do you solve $(7 x + 3) (2 x - 6) = 0$ $(7x+3)(2x-6)=0$ ?

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Answer 1 · 2017-05-12T18:20:44

Solution set for the given equation is ${- \frac{3}{7}, 3}$ ${-3/7 , 3}$

If
$(7 x + 3) (2 x - 6) = 0$ $(7x+3)(2x−6)=0$

then either
$7 x + 3 = 0$ $7x+3=0$
$7 x = - 3$ $7x=-3$
$x = - \frac{3}{7}$ $x=-3/7$

OR
$2 x - 6 = 0$ $2x−6=0$
$2 x = 6$ $2x=6$
$x = \frac{6}{2}$ $x=6/2$
$x = 3$ $x=3$

Hence, the solution set is ${- \frac{3}{7}, 3}$ ${-3/7 , 3}$

How do you solve (7x+3)(2x−6)=0(7x+3)(2x-6)=0?