Question

What is the vertex form of `y= x^2-3x-10`?

Answer 1

minimum vertex at `(3/2, -49/4)`

Explanation:

`y = x^2 - 3 x - 10`

using completing a square,

`y = (x -3/2)^2 - (3/2)^2 -10`

`y = (x -3/2)^2 - 49/4`

since a coeficient of `(x - 3/2)` has a +ve value, we can say that it has a minimum vertex at `(3/2, -49/4)`