A projectile is shot from the ground at a velocity of $86 \frac{m}{s}$ $86 m/s$ and at an angle of $\frac{2 π}{3}$ $(2pi)/3$ . How long will it take for the projectile to land?

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Answer 1 · 2017-05-19T05:46:51

$15.2 sec$ $15.2Sec$

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We know for non inertial frame of reference we have Newtons Laws of motion Valid We can Use the same here

On the Object we have $g$ $g$ acting downwards and U (velocity) has components which we have shown .

From Newtons laws of motion we get
$V = U + a t$ $V=U+at$

if we apply the same here we get
$- U sin θ = U sin θ - g t$ $-Usintheta=Usintheta-g"t"$

similarly we substitute the values to get

$t = \frac{2 \cdot U sin θ}{g}$ $t=(2*Usintheta)/g$
$t = \frac{2 \cdot 86 sin (\frac{2 π}{3})}{9.8} = 15.2 sec$ $t=(2*86sin((2pi)/3))/9.8=15.2Sec$

A projectile is shot from the ground at a velocity of 86ms86 m/s and at an angle of 2π3(2pi)/3. How long will it take for the projectile to land?