What is the vertex form of $y = 5 x^{2} + 22 x + 8$ $y= 5x^2 + 22x + 8$ ?

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Answer 1 · 2017-05-29T19:46:42

$the vertex form of equation is y = 5 {(x + 2.2)}^{2} - 16.2$ $"the vertex form of equation is "y=5(x+2.2)^2-16.2$

$y = 5 x^{2} + 22 x + 8$ $y=5x^2+22x+8$

$The vertex form is can be written as y = a {(x - h)}^{2} - k$ $"The vertex form is can be written as "y=a(x-h)^2-k$

$where (h,k) is vertex coordinates$ $"where (h,k) is vertex coordinates"$

$y = 5 x^{2} + 22 x + 24.2 - 24.2 + 8$ $y=5x^2+22x+color(red)(24.2-24.2)+8$

$y = 5 x^{2} + 22 x + 24.2 - 16.2$ $y=5x^2+22x+24.2-16.2$

$y = 5 (x^{2} + 4.4 x + 4.84) - 16.2$ $y=5(color(green)(x^2+4.4x+4.84))-16.2$

$x^{2} + 4.4 x + 4.84 = {(x + 2.2)}^{2}$ $color(green)(x^2+4.4x+4.84)=(x+2.2)^2$

$y = 5 {(x + 2.2)}^{2} - 16.2$ $y=5(x+2.2)^2-16.2$

What is the vertex form of y= 5x^2 + 22x + 8 y=5x2+22x+8y= 5x^2 + 22x + 8 ?