How do you divide $\frac{6 x^{4} + 4 x^{3} - 12 x^{2} + 2 x - 7}{5 x - 2}$ $(6x^4+4x^3-12x^2+2x-7)/(5x-2)$ ?

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How do you divide $\frac{6 x^{4} + 4 x^{3} - 12 x^{2} + 2 x - 7}{5 x - 2}$ $(6x^4+4x^3-12x^2+2x-7)/(5x-2)$ ?

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Answer 1 · 2017-06-06T00:56:15

$\frac{6}{5} x^{3} + \frac{32}{25} x^{2} - \frac{236}{125} x - \frac{222}{625} - \frac{4819}{625 (5 x - 2)}$ $6/5x^3+32/25x^2-236/125x-222/625-4819/(625(5x-2))$

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How do you divide $\frac{6 x^{4} + 4 x^{3} - 12 x^{2} + 2 x - 7}{5 x - 2}$ $(6x^4+4x^3-12x^2+2x-7)/(5x-2)$ ?

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How do you divide $\frac{6 x^{4} + 4 x^{3} - 12 x^{2} + 2 x - 7}{5 x - 2}$ $(6x^4+4x^3-12x^2+2x-7)/(5x-2)$ ?